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stern plate hydraulic cylinder Sold to Oman

Release time:2023-11-12 15:28:21 Hits: Current position: Home > News

This article mainly introduces:

Oman hydraulic cylinder,stern plate hydraulic cylinder manufacturer,stern plate hydraulic cylinder

Oman stern plate hydraulic cylinder

(Oman stern plate hydraulic cylinder,produced by Hengyu Hydraulic Cylinder Factory)

stern plate hydraulic cylinder are widely used in Oman,because of smooth movement,high work efficiency,excellent fatigue and impact resistance.So our company has designed stern plate hydraulic cylinder for customers from Oman.

Introduction to stern plate hydraulic cylinder:

Do not regularly check the damage of the chrome layer of the stern plate hydraulic cylinder: completely extend the stern plate hydraulic cylinder and carefully check whether there is any surface damage such as injury, strain, welding slag, such as the surface damage position, in the stern plate hydraulic cylinder block < 20cm, and the damage depth < 5mm, should be repaired in time to prevent long-term damage to the stern plate hydraulic cylinder seal. Welding slag is strictly prohibited on the surface of the stern plate hydraulic cylinder.

stern plate hydraulic cylinder piston sealing is best to use Yx ring, polyurethane and polytetrafluoroethylene sealing material combination, can significantly improve the sealing performance: (I), reduce friction resistance, no crawling phenomenon; (ii) Have good dynamic and static sealing, wear resistance, long service life; (iii) The installation groove is simple, and the disassembly is simple.

We can not just consider the price and ignore the quality when we purchase the stern plate hydraulic cylinders. Now some manufacturers produce unqualified products in order to reduce costs, the piston rod is not adjusted, the rod coating is not enough, the stern plate hydraulic cylinder finish can not reach, the guide sleeve should use copper, but instead of ductile iron, although the cost is reduced, the quality of the stern plate hydraulic cylinder is not required.

stern plate hydraulic cylinder piston rod material selection and technical requirements: (I), because there is no special requirements, so use 45 steel as the piston rod material, the design of the piston rod only withstand pressure stress, so no modulation processing; (ii) The coaxial tolerance of the shaft journal and the outer circle of the mounting piston is not greater than 0.01mm, so as to ensure the coaxial degree of the outer circle of the piston rod and the outer circle of the piston, and avoid the stuck phenomenon of the piston and the stern plate hydraulic cylinder, the piston rod and the guide. The vertical tolerance between the end face of the mounting piston and the axis of the piston rod is not more than 0.04mm/100mm to ensure that the piston installation does not produce skew; (iii) The outer circle of the piston rod should pay attention to the roughness; (iv) Because it is operated under low load conditions, surface treatment is omitted.

Answers to some questions about stern plate hydraulic cylinder:

How to choose cylinder size, pump type, motor power for a 30-ton press?
30 tons = 30,000 kg. It is expected to use a 16 mpa oil pump, then the cylinder area =30000/(160x3.14) and then square, the cylinder bore is 150 mm. Calculated at 500 mm travel per minute, the flow rate per minute is :0.75^2x3.14x5=8.8 liters/minute. Motor power =8.8x16/60=2.355. A 9 L/min, 16 mpa pump is available. Piston diameter 150 mm cylinder. 3 kW motor.

What size of hydraulic cylinder is needed for 200 tons pressure? The pressure of the cylinder at work is determined by the load, and the pressure of the physical force is equal to the force divided by the area of action (that is, P=F/S). If you want to calculate the output force of the cylinder, you can calculate by the formula: Set the radius of the piston (that is, the cylinder) is R (unit mm) the radius of the piston rod is r (unit mm) the pressure level P (unit MPa) when working, then the thrust of the cylinder F push =3.14*R*R*P (unit N) the pull of the cylinder F pull =3.14* (R* R-R *R) *P (unit N) 100 tons of the cylinder, System pressure 16Mpa.

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